PHPMem v2.0.1

Version
1.6.45
Uptime
7 days 10 hours 56 minutes 27 seconds

Memory

Total
512MB
Used
13,32MB (2.6%)
Free
498,68MB

Keys

Current
10 162
Total (since start)
11 092
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0
Reclaimed
157
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0
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0

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2 / 1 024 max
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66 536
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0
llm:c85055c98e86df59ec84aff4975c0efa0e223b0f4dd99feba3b0f426235c1788
TTL 11 hours 13 minutes 19 seconds Size 1,80KB Export
Edit
I need to identify all categorical columns and count their distinct values. From the inspect_columns results, I can see several categorical columns (role=dimension or VARCHAR type with relatively low distinct counts). Let me query all of them in a single SQL statement to get their distinct counts efficiently. ```json { "action": "tool_call", "reasoning": "I need to count distinct values for all categorical columns in one query. From the inspect_columns output, I can see columns like task (~15 distinct), model (~325), Organization (~21), Domain (~20), etc. I'll write a single SELECT with COUNT(DISTINCT col) for all categorical columns to get the complete picture efficiently.", "tool": "query_sql", "sql": "SELECT COUNT(DISTINCT task) as task_distinct, COUNT(DISTINCT model) as model_distinct, COUNT(DISTINCT \"Best score (across scorers)\") as best_score_distinct, COUNT(DISTINCT Status) as status_distinct, COUNT(DISTINCT \"Manual evaluation\") as manual_evaluation_distinct, COUNT(DISTINCT \"task version\") as task_version_distinct, COUNT(DISTINCT id_model_version) as id_model_version_distinct, COUNT(DISTINCT \"Model__1\") as model_1_distinct, COUNT(DISTINCT \"Hugging Face developer id\") as hugging_face_dev_id_distinct, COUNT(DISTINCT \"Display name\") as display_name_distinct, COUNT(DISTINCT \"Unique display name\") as unique_display_name_distinct, COUNT(DISTINCT Domain) as domain_distinct, COUNT(DISTINCT \"Task__1\") as task_1_distinct, COUNT(DISTINCT Organization) as organization_distinct, COUNT(DISTINCT \"Version release date\") as version_release_date_distinct FROM raw.benchmarks", "purpose": "Count distinct values for all major categorical columns in a single query" } ```